4[3+U]-U=6+3[U+2]

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Solution for 4[3+U]-U=6+3[U+2] equation: 


Simplifying
4[3 + U] + -1U = 6 + 3[U + 2]
[3 * 4 + U * 4] + -1U = 6 + 3[U + 2]
[12 + 4U] + -1U = 6 + 3[U + 2]

Combine like terms: 4U + -1U = 3U
12 + 3U = 6 + 3[U + 2]

Reorder the terms:
12 + 3U = 6 + 3[2 + U]
12 + 3U = 6 + [2 * 3 + U * 3]
12 + 3U = 6 + [6 + 3U]

Combine like terms: 6 + 6 = 12
12 + 3U = 12 + 3U

Add '-12' to each side of the equation.
12 + -12 + 3U = 12 + -12 + 3U

Combine like terms: 12 + -12 = 0
0 + 3U = 12 + -12 + 3U
3U = 12 + -12 + 3U

Combine like terms: 12 + -12 = 0
3U = 0 + 3U
3U = 3U

Add '-3U' to each side of the equation.
3U + -3U = 3U + -3U

Combine like terms: 3U + -3U = 0
0 = 3U + -3U

Combine like terms: 3U + -3U = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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